Optimal. Leaf size=94 \[ -\frac {1}{6} (5 x+3)^{3/2} (1-2 x)^{3/2}-\frac {11}{16} \sqrt {5 x+3} (1-2 x)^{3/2}+\frac {121}{160} \sqrt {5 x+3} \sqrt {1-2 x}+\frac {1331 \sin ^{-1}\left (\sqrt {\frac {2}{11}} \sqrt {5 x+3}\right )}{160 \sqrt {10}} \]
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Rubi [A] time = 0.02, antiderivative size = 94, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 3, integrand size = 19, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.158, Rules used = {50, 54, 216} \begin {gather*} -\frac {1}{6} (5 x+3)^{3/2} (1-2 x)^{3/2}-\frac {11}{16} \sqrt {5 x+3} (1-2 x)^{3/2}+\frac {121}{160} \sqrt {5 x+3} \sqrt {1-2 x}+\frac {1331 \sin ^{-1}\left (\sqrt {\frac {2}{11}} \sqrt {5 x+3}\right )}{160 \sqrt {10}} \end {gather*}
Antiderivative was successfully verified.
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Rule 50
Rule 54
Rule 216
Rubi steps
\begin {align*} \int \sqrt {1-2 x} (3+5 x)^{3/2} \, dx &=-\frac {1}{6} (1-2 x)^{3/2} (3+5 x)^{3/2}+\frac {11}{4} \int \sqrt {1-2 x} \sqrt {3+5 x} \, dx\\ &=-\frac {11}{16} (1-2 x)^{3/2} \sqrt {3+5 x}-\frac {1}{6} (1-2 x)^{3/2} (3+5 x)^{3/2}+\frac {121}{32} \int \frac {\sqrt {1-2 x}}{\sqrt {3+5 x}} \, dx\\ &=\frac {121}{160} \sqrt {1-2 x} \sqrt {3+5 x}-\frac {11}{16} (1-2 x)^{3/2} \sqrt {3+5 x}-\frac {1}{6} (1-2 x)^{3/2} (3+5 x)^{3/2}+\frac {1331}{320} \int \frac {1}{\sqrt {1-2 x} \sqrt {3+5 x}} \, dx\\ &=\frac {121}{160} \sqrt {1-2 x} \sqrt {3+5 x}-\frac {11}{16} (1-2 x)^{3/2} \sqrt {3+5 x}-\frac {1}{6} (1-2 x)^{3/2} (3+5 x)^{3/2}+\frac {1331 \operatorname {Subst}\left (\int \frac {1}{\sqrt {11-2 x^2}} \, dx,x,\sqrt {3+5 x}\right )}{160 \sqrt {5}}\\ &=\frac {121}{160} \sqrt {1-2 x} \sqrt {3+5 x}-\frac {11}{16} (1-2 x)^{3/2} \sqrt {3+5 x}-\frac {1}{6} (1-2 x)^{3/2} (3+5 x)^{3/2}+\frac {1331 \sin ^{-1}\left (\sqrt {\frac {2}{11}} \sqrt {3+5 x}\right )}{160 \sqrt {10}}\\ \end {align*}
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Mathematica [A] time = 0.06, size = 69, normalized size = 0.73 \begin {gather*} \frac {3993 \sqrt {20 x-10} \sinh ^{-1}\left (\sqrt {\frac {5}{11}} \sqrt {2 x-1}\right )-10 \sqrt {5 x+3} \left (1600 x^3+680 x^2-1154 x+207\right )}{4800 \sqrt {1-2 x}} \end {gather*}
Antiderivative was successfully verified.
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IntegrateAlgebraic [A] time = 0.14, size = 109, normalized size = 1.16 \begin {gather*} -\frac {1331 \sqrt {1-2 x} \left (\frac {75 (1-2 x)^2}{(5 x+3)^2}+\frac {80 (1-2 x)}{5 x+3}-12\right )}{480 \sqrt {5 x+3} \left (\frac {5 (1-2 x)}{5 x+3}+2\right )^3}-\frac {1331 \tan ^{-1}\left (\frac {\sqrt {\frac {5}{2}} \sqrt {1-2 x}}{\sqrt {5 x+3}}\right )}{160 \sqrt {10}} \end {gather*}
Antiderivative was successfully verified.
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fricas [A] time = 1.69, size = 67, normalized size = 0.71 \begin {gather*} \frac {1}{480} \, {\left (800 \, x^{2} + 740 \, x - 207\right )} \sqrt {5 \, x + 3} \sqrt {-2 \, x + 1} - \frac {1331}{3200} \, \sqrt {10} \arctan \left (\frac {\sqrt {10} {\left (20 \, x + 1\right )} \sqrt {5 \, x + 3} \sqrt {-2 \, x + 1}}{20 \, {\left (10 \, x^{2} + x - 3\right )}}\right ) \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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giac [B] time = 1.11, size = 140, normalized size = 1.49 \begin {gather*} \frac {1}{4800} \, \sqrt {5} {\left (2 \, {\left (4 \, {\left (40 \, x - 59\right )} {\left (5 \, x + 3\right )} + 1293\right )} \sqrt {5 \, x + 3} \sqrt {-10 \, x + 5} + 4785 \, \sqrt {2} \arcsin \left (\frac {1}{11} \, \sqrt {22} \sqrt {5 \, x + 3}\right )\right )} + \frac {3}{200} \, \sqrt {5} {\left (2 \, {\left (20 \, x - 23\right )} \sqrt {5 \, x + 3} \sqrt {-10 \, x + 5} - 143 \, \sqrt {2} \arcsin \left (\frac {1}{11} \, \sqrt {22} \sqrt {5 \, x + 3}\right )\right )} + \frac {9}{50} \, \sqrt {5} {\left (11 \, \sqrt {2} \arcsin \left (\frac {1}{11} \, \sqrt {22} \sqrt {5 \, x + 3}\right ) + 2 \, \sqrt {5 \, x + 3} \sqrt {-10 \, x + 5}\right )} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 0.00, size = 88, normalized size = 0.94 \begin {gather*} \frac {1331 \sqrt {\left (-2 x +1\right ) \left (5 x +3\right )}\, \sqrt {10}\, \arcsin \left (\frac {20 x}{11}+\frac {1}{11}\right )}{3200 \sqrt {5 x +3}\, \sqrt {-2 x +1}}+\frac {\left (5 x +3\right )^{\frac {5}{2}} \sqrt {-2 x +1}}{15}-\frac {11 \left (5 x +3\right )^{\frac {3}{2}} \sqrt {-2 x +1}}{120}-\frac {121 \sqrt {-2 x +1}\, \sqrt {5 x +3}}{160} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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maxima [A] time = 1.45, size = 55, normalized size = 0.59 \begin {gather*} -\frac {1}{6} \, {\left (-10 \, x^{2} - x + 3\right )}^{\frac {3}{2}} + \frac {11}{8} \, \sqrt {-10 \, x^{2} - x + 3} x - \frac {1331}{3200} \, \sqrt {10} \arcsin \left (-\frac {20}{11} \, x - \frac {1}{11}\right ) + \frac {11}{160} \, \sqrt {-10 \, x^{2} - x + 3} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.01 \begin {gather*} \int \sqrt {1-2\,x}\,{\left (5\,x+3\right )}^{3/2} \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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sympy [A] time = 4.72, size = 230, normalized size = 2.45 \begin {gather*} \begin {cases} \frac {50 i \left (x + \frac {3}{5}\right )^{\frac {7}{2}}}{3 \sqrt {10 x - 5}} - \frac {275 i \left (x + \frac {3}{5}\right )^{\frac {5}{2}}}{12 \sqrt {10 x - 5}} - \frac {121 i \left (x + \frac {3}{5}\right )^{\frac {3}{2}}}{48 \sqrt {10 x - 5}} + \frac {1331 i \sqrt {x + \frac {3}{5}}}{160 \sqrt {10 x - 5}} - \frac {1331 \sqrt {10} i \operatorname {acosh}{\left (\frac {\sqrt {110} \sqrt {x + \frac {3}{5}}}{11} \right )}}{1600} & \text {for}\: \frac {10 \left |{x + \frac {3}{5}}\right |}{11} > 1 \\\frac {1331 \sqrt {10} \operatorname {asin}{\left (\frac {\sqrt {110} \sqrt {x + \frac {3}{5}}}{11} \right )}}{1600} - \frac {50 \left (x + \frac {3}{5}\right )^{\frac {7}{2}}}{3 \sqrt {5 - 10 x}} + \frac {275 \left (x + \frac {3}{5}\right )^{\frac {5}{2}}}{12 \sqrt {5 - 10 x}} + \frac {121 \left (x + \frac {3}{5}\right )^{\frac {3}{2}}}{48 \sqrt {5 - 10 x}} - \frac {1331 \sqrt {x + \frac {3}{5}}}{160 \sqrt {5 - 10 x}} & \text {otherwise} \end {cases} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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